Apasz
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Homework Statement
prove that lim n→∞ of \sum^{n}_{k=0} e^{-n} n^{k} / k! = 1/2
The Attempt at a Solution
I seem to be mishandling the series. After taking n→∞, the sum of (n^k)/k! is just the taylor series expansion of e^n. Then I should get e^(-n)*e^n = 1.
Where am I going wrong??
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