Limit w/Tangent: Solve & Discuss

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SUMMARY

The limit problem presented involves evaluating the expression \(\lim_{x \rightarrow 1}(1-x)\tan{\left(\frac{\pi x}{2}\right)}\), which is solved using L'Hospital's rule to yield a result of \(\frac{2}{\pi}\). An alternative method is also discussed, where the substitution \(y = x - 1\) leads to the same limit evaluation, confirming the result of \(\frac{2}{\pi}\). The discussion highlights the effectiveness of both L'Hospital's rule and substitution techniques in solving limits involving trigonometric functions.

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Homework Statement



Solve the following limit:

\lim_{x \rightarrow 1}(1-x)\tan{\left(\frac{\pi x}{2}\right)}

The Attempt at a Solution



I solved it using L'Hospital rule, it's equal to 2/pi, but is there any other way how to solve it? thanks a lot!

The same question would apply to

\lim_{x \rightarrow \frac{\pi}{3}}\left(\frac{\sin{\left(x-\frac{\pi}{3}\right)}}{1-2\cos{x}}\right)
 
Last edited:
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Well, I've finally found a different way how to solve it... I post it here since it can be useful to someone..

I substituted x with y = x-1, and then after some steps I've arrived at the following limit:

\lim_{y \rightarrow 0}\frac{\frac{\pi}{2}y}{\sin{\frac{\pi}{2}y}}\frac{2}{\pi}\cos{\frac{\pi}{2}y} = \frac{2}{\pi}
 

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