Line integral question

  • Thread starter asdf1
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  • #1
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Calculate the line integral of the function v=(y的平方, 2x(y+1), 0) from the
point a=(1,0,0) to the point b=(2,2,0)
The correct Ans: 11

However, when I was calculuating the problem,
I supposed(is that the right word?) to make the parameter equations,

x=1+t
y=1+t
z=0
where 0<t<1
but when I integrated the function, the answer is 6.
 

Answers and Replies

  • #2
13
0
i don't know why, but i see your function as some chinese characters, can you retype it in some other way:).
 
  • #3
TD
Homework Helper
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Are you sure about that parametrization of your path?

I'd say

[tex]\left\{ \begin{array}{l}
x = t \\
y = 2t - 2 \\
z = 0 \\
\end{array} \right[/tex]

or

[tex]\left\{ \begin{array}{l}
x = t + 1 \\
y = 2t \\
z = 0 \\
\end{array} \right[/tex]
 
  • #4
HallsofIvy
Science Advisor
Homework Helper
41,833
956
asdf1 said:
Calculate the line integral of the function v=(y的平方, 2x(y+1), 0) from the
point a=(1,0,0) to the point b=(2,2,0)
The correct Ans: 11

However, when I was calculuating the problem,
I supposed(is that the right word?) to make the parameter equations,

x=1+t
y=1+t
z=0
where 0<t<1
but when I integrated the function, the answer is 6.
when t= 0, your parametrization gives (1, 1, 0), there is no value of t that gives (1, 0, 0).
 
  • #5
734
0
sorry, i mistyped~
a=(1,0,0)
 

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