Linear Algebra and Matrices, Subspaces, basis

AI Thread Summary
A linearly independent set of x vectors in an x-dimensional subspace C of Rn is indeed a basis for C, as it meets the criteria of having independent vectors and the correct number of vectors. The discussion emphasizes that the definition of dimension includes the requirement that the basis must span the subspace. If there are x independent vectors, they will span the x-dimensional space. The properties of a basis are confirmed: independence, spanning, and the number of vectors matching the dimension. Therefore, the initial statement about the basis is correct.
war485
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Homework Statement



I'm unclear about this statement being wrong or not:
if C is an x-dimensional subspace of Rn, then a linearly independent set of x vectors in C is a basis for C

The Attempt at a Solution



I think that it must be a basis since it has independent vectors and it is in x dimensions, so there are x vectors in it. What I'm not so sure about is whether or not if it spans the subspace, but I think it does since all the vectors are independent, so there are x of them, so it should span in x dimensions.

I also want to thank HallsofIvy for lots of help with me with the questions 2 days ago.
 
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Sure it's right. Isn't that the definition of dimension? The number of independent vectors required to span C?
 
If V is a vector space of dimension N, then a basis for V has three properties:
1) The vectors in the basis are independent.
2) The vectors span V.
3) There are N vectors in the basis.

If any two of those are true, the third is also.
 
Thanks you two. :)
 
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