Linear algebra - change of basis matrix

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To find the representation of vector u with respect to basis A given its representation with respect to basis B, the transition matrix from B to A is utilized. The vector u is calculated as u = 3*(0,2) - 2*(2,1), resulting in u = (-4, 4). To express u in terms of basis A, the equations a*(1, 1) + b*(2, 0) = (-4, 4) are solved, yielding a = 4 and b = -4. Thus, the final representation of u with respect to basis A is [u]A = [4, -4]. The solution confirms the correct application of linear algebra concepts.
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Homework Statement



Let A = {(1, 1), (2,0)} and B = {(0, 2), (2, 1)} in R2.
a) Find A (u with respect to A) if B = [3, -2].

Homework Equations





The Attempt at a Solution



I tried to find AB (transition matrix from B to A), then apply to B, but couldn't represent (2, 1) with respect to A?

So I found u by BB = u,
then u = (4, -4).

Now represent u with respect to A:
A = (-4, 4)

Is this correct?
 
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Yes, that's how it's done. You don't need to bother too much.
We know that _B=[3,-2]^t => u=3*(0,2)-2*(2,1)=(-4,4).
Now, in order to find _A we need to find a,b in R such that :
a*(1, 1)+b*(2,0)=(-4,4) => a+2b=-4 and a=4 => a=4 and b=-4.
Therefore : _A = [4,-4]^t.
DONE! :)
 
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