Linear algebra help: Linear independence

epkid08
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Homework Statement


Let A be an m x n matrix of rank n. Suppose v_1, v_2, ..., v_k \in \mathbb{R}^n and \{v_1, v_2, ..., v_k\} is linearly independent. Prove that \{Av_1, Av_2, ..., Av_k\} is likewise linearly independent.



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The Attempt at a Solution


It says I need to use rank(A) = n, but I'm not sure how to use that info.
 
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Rank n tells you that if you have a basis e_1, e_2, ..., e_n of \mathbb{R}^n then A(e_1), A(e_2), ..., A(e_n) are linearly independent. I.e. A takes R^n into an n-dimensional subspace of R^m.
 
have you proven a subset of a linearly independent set is also linearly independent?

if so, extend the v's to a basis.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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