Linear Algebra - homogeneous equation

Inertigratus
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Homework Statement


The problem is setting up the equation, it says that the matrix equation will be made up of four equations for the 2 unknowns.
I'm supposed to find for which a's and b's the equation is true, using a linear system and gaussian elimination.

Homework Equations


A2 + aA + bI2 = 0
A = | 3 1|
...| 4 -2|
I2 = identity matrix, 2x2
A2 = | 13 5 |
...| 4 8 |

The Attempt at a Solution


I'm not sure how to proceed with this problem.
How do I split the equation into 4 equations with respect to the variables a and b?
 
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When you plug in the known matrices A^2, aA, bI_s you will get a 2 \times 2 matrix on the left side: it has four entries. On the right you have the matrix

<br /> \begin{bmatrix} 0 &amp; 0 \\ 0 &amp; 0 \end{bmatrix}<br />

Write down the left matrix and right matrix: what do you see?
 
Isn't it 4 x 3?
13 + 3a + b
5 + a
4 + 4a
8 - 2a + b
on the left side?
 
You have four equations on the left - how many constants are on the right?
 
4? since all equation are equal to zero?
I guess I could move the constans to the right side. Then I would have four rows x three columns.
 
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Inertigratus said:
4? since all equation are equal to zero?
I guess I could move the constans to the right side. Then I would have four rows x three columns.

You have 4 equations, one for each entry in the 2 \times 2 matrix.
When you move all constants to the right you end up with four equations in two unknowns. I have not worked through the solution so I can't tell you what to expect when you move on to solving for the unknowns.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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