Linear Algebra - Matrix Multiplication

jofree87
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| 1 1 1 | = matrix A
| 1 2 3 |
| 1 4 5 |

How do I find a 3x3 matrix B, excluding the identity or zero matrix, such that AB = BA?
 
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I think if you create and multiply by a diagonal matrix, it would work.
I know for sure that if A and B are diagonal matrices, AB=BA
 
You could make a matrix of entries a b c d e f g h i and let that be matrix B,and you can then multiply AB and BA, and equate each entry or make a system of equations out of it and find what value each letter has in terms of the other letters. There may be an easier way I'm tired.
 
jofree87 said:
| 1 1 1 | = matrix A
| 1 2 3 |
| 1 4 5 |

How do I find a 3x3 matrix B, excluding the identity or zero matrix, such that AB = BA?
The inverse of A, A-1, is a matrix for which AA-1 = A-1A. Do you know how to find the inverse of a given matrix?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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