Linear Algebra - Matrix Multiplication

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Homework Help Overview

The discussion revolves around finding a 3x3 matrix B that commutes with a given matrix A, specifically that AB = BA, while excluding the identity and zero matrices. The subject area is linear algebra, focusing on matrix multiplication and properties of matrices.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using diagonal matrices as a potential solution, noting that diagonal matrices commute with each other. Others propose defining matrix B with variables and equating the products AB and BA to derive a system of equations. There is also a mention of the inverse of matrix A and its properties related to commutation.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants have offered guidance on using specific types of matrices, while others are questioning the setup and considering different methods to find matrix B.

Contextual Notes

Participants are working under the constraint of excluding the identity and zero matrices from their considerations. There is also a reference to the inverse of matrix A, which may imply a need for further exploration of matrix properties.

jofree87
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| 1 1 1 | = matrix A
| 1 2 3 |
| 1 4 5 |

How do I find a 3x3 matrix B, excluding the identity or zero matrix, such that AB = BA?
 
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I think if you create and multiply by a diagonal matrix, it would work.
I know for sure that if A and B are diagonal matrices, AB=BA
 
You could make a matrix of entries a b c d e f g h i and let that be matrix B,and you can then multiply AB and BA, and equate each entry or make a system of equations out of it and find what value each letter has in terms of the other letters. There may be an easier way I'm tired.
 
jofree87 said:
| 1 1 1 | = matrix A
| 1 2 3 |
| 1 4 5 |

How do I find a 3x3 matrix B, excluding the identity or zero matrix, such that AB = BA?
The inverse of A, A-1, is a matrix for which AA-1 = A-1A. Do you know how to find the inverse of a given matrix?
 

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