Linear Algebra Matrix with Elementary Row Operations

lina29
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Homework Statement



The 3x3 matrix A is transformed into I by the following elementary row operations
R1+2R3 -> R1
R2+2R3 ->R2
2R2 ->R2
R1 <->R2
2R3 ->R3

Find det(A)

Homework Equations



I assumed to start off with the problem since I was going backwards from I to A. I would do the opposite of each row operation ie
2R3-R1 ->R1
2R3-R2 ->R2
(1/2)R2 ->R2
R1 <->R2
(1/2)R3 ->R3

The Attempt at a Solution



By finding the det(A) I got -1/4. I'm confused on if I messed up on the row operations. When I did this problem without using the backwards row operations I got -4 which was also wrong. I'd appreciate any help

Thanks
 
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Of the three elementary row operations, only one of them changes the value of the determinant of the matrix. Do you know which one this is?

Since you end up with the identity matrix (det(I) = 1), you can pick out the row operations that affect the determinant, to get the determinant of your starting matrix.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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