Linear Algebra? (Or Differential Equation?)

mudkip123
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Find un, vn, and tn in terms of n for the following system:
{
un+1 = -un + 2vn + tn
vn+1 = vn - tn
tn+1 = 2tn

For u0, v0, t0 given



This isn't homework, it's on a study guide for my midterm.
 
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welcome to pf!

hi mudkip123! welcome to pf! :smile:

you're looking for a combination an = Aun + Bvn + Ctn such that an+1 = Dan :wink:
 
mudkip123 said:
Find un, vn, and tn in terms of n for the following system:
{
un+1 = -un + 2vn + tn
vn+1 = vn - tn
tn+1 = 2tn

For u0, v0, t0 given



This isn't homework, it's on a study guide for my midterm.

First solve the third one t_{n+1} = 2 t_n, to get t_n = t_0 2^{n-1}. Now look at the second one v_{n+1} = v_n -t_n. It gives v_n = v_0 -\sum_{j=0}^{n-1} t_j, which is computable. Now you have u_{n+1} = -u_n + f(n) with a known function f(n), so you can solve it easily: u_1 = f(0)-u_0, \; u_2 = f(1) - u_1 = f(1)-f(0) + u_0, \; u_3 = f(2) - u_2 = f(2)-f(1)+f(0) - u_0, etc.

RGV
 
This isn't in my linear algebra textbook so I don't know how to do this...
 
You have been given enough hints. We will only help you further if you make an attempt now.
 
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