Linear algebra proof - inverses

miky87
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Homework Statement



Let m < n. Let A be an n × m matrix, and let B be an m × n matrix. Prove that AB /= In .


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The Attempt at a Solution


since m<n, the reduced form of matrix B will have free variables.
I know that if A and B are invertible matrices, AB will be as well but does the converse also hold?
 
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Hi miky87! :smile:

miky87 said:
I know that if A and B are invertible matrices, AB will be as well but does the converse also hold?

This makes no sense. A matrix can only be invertible when it's square. And these are not square matrices.

What can you tell us about the rank of A, B, AB and In??
 
The question make perfect sense: he is being asked to show that A*B cannot be the identity matrix (i.e., that a non-square matrix cannot have a left- or right-inverse). This seems closely related to another question in this Forum, and the same advice given there applies here.

RGV
 
Ray Vickson said:
The question make perfect sense: he is being asked to show that A*B cannot be the identity matrix (i.e., that a non-square matrix cannot have a left- or right-inverse). This seems closely related to another question in this Forum, and the same advice given there applies here.

RGV

A matrix A is invertible if and only if there is a matrix B such that AB=BA=I. This can only be satisfied for square matrices. So calling A and B invertible in his question does not make any sense.
Left and right inverses do make sense, but I doubt he meant that.
 
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