Linear Dependence and Non-Zero Coefficients

AI Thread Summary
The discussion centers on the concept of linear dependence among vectors u, v, and w. The statement in question is whether the equation au + bv + cw = 0 implies that at least one of the coefficients a, b, or c must be non-zero if the vectors are linearly dependent. The confusion arises from the fact that the zero vector equation can hold true regardless of the coefficients being zero. It is clarified that while linear dependence allows for the possibility of zero coefficients, it does not necessitate that at least one must be non-zero. Understanding this subtlety is crucial for grasping the definition of linear dependence.
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Homework Statement



True or False:

If u, v, and w are linearly dependent, then au+bv+cw=0 implies at least one of the coefficients a, b, c is not zero

Homework Equations



Definition of Linear Dependence:

Vectors are linearly dependent if they are not linearly independent; that is there is an equation of the form c_{1}v_{1}+c_{2}v_{2}+\dots+c_{n}v_{n} with at least one coefficient not zero

The Attempt at a Solution



I said true, but the book says false. It gives the reason, "for any vectors u, v, w - linearly dependent or not - 0u+0v+0w = 0" . But isn't the problem a direct restatement of the definition? Or am I missing something subtle here.
 
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Morgan Chafe said:

Homework Statement



True or False:

If u, v, and w are linearly dependent, then au+bv+cw=0 implies at least one of the coefficients a, b, c is not zero

Homework Equations



Definition of Linear Dependence:

Vectors are linearly dependent if they are not linearly independent; that is there is an equation of the form c_{1}v_{1}+c_{2}v_{2}+\dots+c_{n}v_{n} with at least one coefficient not zero

The Attempt at a Solution



I said true, but the book says false. It gives the reason, "for any vectors u, v, w - linearly dependent or not - 0u+0v+0w = 0" . But isn't the problem a direct restatement of the definition? Or am I missing something subtle here.
You're missing something subtle.
 
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If u, v, w linearly independent, au+bv+cw=0 implies a=b=c=0.
Inverting that, if u, v, w linearly dependent, au+bv+cw=0 does not imply a=b=c=0. But they still could be 0.
 
Thanks
 
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