1. The problem statement, all variables and given/known data A glass tube of radius 0.80cm contains liquid mercury to a depth of 64.0cm at 12degrees. Find the depth of the mercury column at 100degrees. Assume that the linear expansion coefficient of the glass is 10x10^-6K-1 and the linear expansion coefficient of mercury is 0.61x10^-4K-1. 2. Relevant equations L - Lo = alpha * Lo (T - To) 3. The attempt at a solution With the knowns, I was able to figure out the depth of the mercury at 100degrees using the above equation, however, the radius and the linear expansion coefficent of the glass was also given. How do I put that into account?? Can someone guide me please??