Understanding Linear Functionals: Help Me w/ Example Problem!

wurth_skidder_23
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I am studying for a final I have tomorrow in linear algebra, and I am still having trouble understanding linear functionals. Can someone help me out with this example problem, walk me through it so I can understand exactly what a linear functional is?

Is the following a linear functional?

\ y (x)=\int_0^1\ t^2 x(t) \, dx
\ y (x)=x(-2)+\int_0^1\ x(t^2)\, dt
 
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Always start by going back to the definitions.
 
For the second one, which is basically just an addition to the first, is this correct?

Property 1 of a linear functional is satisfied as follows:
\ y (x+z)=x(-2)+z(-2)+\int_0^1\ (x(t^2)+z(t^2))\, dt
\ y (x+z)=x(-2)+\int_0^1\ x(t^2)\, dt + z(-2)+\int_0^1\ z(t^2)\, dt
\ y (x+z)=y(x)+y(z)

Property 2 of a linear function is satisfied similarly:
\ y(a x)=a x(-2)+\int_0^1\ a x(t^2)\, dt
\ y(a x)=a (x(-2)+\int_0^1\ x(t^2)\, dt)
\ y(a x)=a y(x)
 
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It's as easy as that.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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