Linear Transformation / Coordinate Vector Question

Gotejjeken
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Homework Statement


The following vectors form an ordered basis E = [v1, v2] of the subspace V = span(v1,v2):

v1 = (1,2,1)^T , v2 = (3,2,1)^T.

The vector v = (24,-8,-4)^T belongs to the subspace V. Find its coordinates (c1,c2)^T = [v]E relative to the ordered basis E = [v1,v2].

Homework Equations



None.

The Attempt at a Solution



I am not quite sure how to approach this problem. I wanted to calculate the inverse of:

1 3
2 2
1 1

and then multiply v = (24, -8, -4)^T by the inverse to get the coordinate vector relative to E, however I have no idea if that is the right approach. I feel I'm missing something...
 
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Gotejjeken said:

Homework Statement


The following vectors form an ordered basis E = [v1, v2] of the subspace V = span(v1,v2):

v1 = (1,2,1)^T , v2 = (3,2,1)^T.

The vector v = (24,-8,-4)^T belongs to the subspace V. Find its coordinates (c1,c2)^T = [v]E relative to the ordered basis E = [v1,v2].

Homework Equations



None.

The Attempt at a Solution



I am not quite sure how to approach this problem. I wanted to calculate the inverse of:

1 3
2 2
1 1
The only matrices that have inverses are square matrices. The one you show above is 3 x 2, so isn't square.
Gotejjeken said:
and then multiply v = (24, -8, -4)^T by the inverse to get the coordinate vector relative to E, however I have no idea if that is the right approach. I feel I'm missing something...

Solve the equation below for the constants c1 and c2.
(24, -8, -4)^T = c1*(1,2,1)^T + c2*(3,2,1)^T
 
Oh, wow. Thank you, it seems I was over-complicating things...the wording of that problem had my brain in knots.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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