Linear Transformation - Linear Algebra

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Homework Help Overview

The discussion revolves around determining the linearity of a transformation T defined as T(x,y,z) = (1,1). Participants are exploring the properties of linear transformations within the context of linear algebra.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand why the transformation is not linear, questioning the implications of the transformation's constant output. Some participants suggest writing out the transformation for scalar multiplication and comparing it to the expected results. Others raise concerns about the nature of constant transformations in the context of vector spaces.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem. There is acknowledgment of the need to uphold both the homogeneity and additivity principles for linear transformations. The original poster expresses a moment of clarity after engaging with the responses.

Contextual Notes

Participants are navigating the definitions and properties of linear transformations, particularly focusing on the implications of a transformation that yields a constant output regardless of input variables.

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[SOLVED] Linear Transformation - Linear Algebra

Homework Statement



Determine if T is linear. T(x,y,z) = (1,1)

Homework Equations



Definition of Linear Transformation: A function T: R^n --> R^m is a linear transformation if for all u and v in R^n and all scalars c, the following principles are satisfied:

Homogeneity Principle: T(cu) = cT(u)
Additivity Principle: T(u+v) = T(u) + T(v)

The Attempt at a Solution



The answer that was given for this question is false, and I am trying to see why. Therefore, this is what I've done but I am missing something because I always get true if I am to assume that T(cx, cy, cz) = (c,c) but the answer is supposed to be (1,1).

My reason thus far has been to say that because there are no variables in the solution of the transformation (1,1), then a scalar cannot be multiplied to it, but that doesn't make sense because it should work for all vectors, regardless of whether they are numbers or letters. The answer my prof gave was this:

T(cx, cy, cz) = (1,1) which does not equal c(1,1) = cT(x,y,z). He didn't bother with the addivitivity since both principles need to be upheld for the transformation to be linear.

If you could clarify, I would really appreciate it!
 
Physics news on Phys.org
1. Write out T(cu)
2. Write out T(u)
3. Multiply "2" with c
4. Compare "3" with "1"
 
Constant transformations should send up red flags. Remember that linear transformations form a vector space. So they need to work with the kind of manipulations EnumaElish described.
 
I see it now! Thanks so much!
 

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