Linear Transformation matrix help

cwatki14
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The problem is as follows:
Find a nonzero 2x2 matrix A such that Ax is parallel to the vector
[1]
[2]
for all x in R2.

So far I know A=[v1 v2] therefore Ax= [v1 v2][x1]
[x2]

= x1v1+x2v2
I know these two vectors are parallel, but I am a little stuck how to relate this property to solve for the matrix A.
 
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You have Ax = k[1 2]T for any vector x in R2.
Specify values for A.

What does A do to [1 0]T? to [0 1]T?
 
What Mark44 suggests works fine. A more "primitive method" is to write A as
\begin{bmatrix}a & b \\ c & d\end{bmatrix}
so your equation "Ax= k[1 2]T" becomes
\begin{bmatrix}a & b \\ c & d\end{bmatrix}\begin{bmatrix} x \\ y\end{bmatrix}= \begin{bmatrix}ax+ by \\ cx+ dy\end{bmatrix}= \begin{matrix}k \\ 2k\end{bmatrix}[/tex]

giving you two equations, ax+ by= k and cx+ dy= 2k for the 5 unknown numbers. There will, of course, be an infinite number of possible answers. You are simply asked to find one such matrix.
 
Note: fixed your LaTeX by adding a missing [ tex] tag.
HallsofIvy said:
What Mark44 suggests works fine. A more "primitive method" is to write A as
\begin{bmatrix}a & b \\ c & d\end{bmatrix}
so your equation "Ax= k[1 2]T" becomes
\begin{bmatrix}a & b \\ c & d\end{bmatrix} \begin{bmatrix} x \\ y\end{bmatrix}= \begin{bmatrix}ax+ by \\ cx+ dy\end{bmatrix}= \begin{matrix}k \\ 2k\end{bmatrix}

giving you two equations, ax+ by= k and cx+ dy= 2k for the 5 unknown numbers. There will, of course, be an infinite number of possible answers. You are simply asked to find one such matrix.
That's what I meant by saying "specify values for A." I think we're on the same page here.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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