Linear Transformation Question: Solving for Im(T) in R^4 Dimension Space

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The discussion focuses on solving a linear transformation problem in R^4, specifically determining the image of the transformation, Im(T). Given that the dimension of the kernel, dim(Ker(T)), is 2 and the total dimension dim(V) is 4, it follows that dim(Im(T)) is also 2. To find the specific linear transformation, the transformation can be represented as a 4x4 matrix A, leading to 16 unknowns. By applying the condition Ax=0 for vectors in the kernel, 8 equations are derived, indicating the need for additional assumptions to solve for the remaining unknowns. A suggested approach is to consider a projection matrix that maps the kernel plane to zero while preserving components perpendicular to that plane.
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I need help with question from homework in linear algebra.

This question (linear transformation):
http://i43.tinypic.com/15reiic.gif

According to theorem dimensions:
dim(V) = dim(Ker(T)) + dim(Im(T)).

dim(Ker(T))=2.
dim(V) in R^4, meaning =4.

We can therefore conclude that dim(Im(T))=2.
But how can find this specific linear transformation?

Please help me to solve this problem.
Thanks.
 
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So let's write the transform as a 4x4 matrix A, giving 16 unknowns.

Now you you know Ax=0 for, x in the kernal. This gives you 8 equations, and is equivalent to mappint the plane contain the 2 kernal vectors to zero.

Clearly you still have more unknowns, so you will need to make some assumptions.

One of the simpler ones, might be to try and find the "projection matrix" which maps components in the kernal plane to zero, but leaves components perpindicular to that plane unchanged
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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