Linearization of an equation around fixed points

darkspym7
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Homework Statement


Find the linearization of the equation y' = y(-1+4y-3y^2) about each of the fixed points


The Attempt at a Solution


I think this is correct for finding fixed points:
Set y' = 0 = y(-1+4y+3y^2), so the fixed points are y = 0, 1/3, 1

What exactly does it mean by linearization of the equation around each of the fixed points?
 
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linearization

the linearization of a function f about a, (linearization at x=a) is
L(x)= f(a)+f'(a)(x-a) Its pretty much like a taylor series approximation.
 
example

find the linearization of f(x)=x^2 about x=3

L(x)=f(3)+f'(3)(x-3)
L(x)=9+6(x-3)=6x-9
 
But using those fixed points, f'(a) would always be 0. Are those the correct fixed points?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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