- #1
JSBeckton
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A liquid water turbine receives 2kg/s water at 2000kPa, 20C, and velocity of 15m/s. The exit is at 100kPa, 20C and very low velocity. Find specific work and power produced.
From my tables I get
hi=85.82 kJ/kg
he=84.03 kJ/kg
Energy equation reduces to:
[tex]
\begin{array}{l}
h_i + \frac{{V_i^2 }}{2} = \omega + h_e \\
\omega = h_i + \frac{{V_i^2 }}{2} - h_e \\
\omega = 85.82\frac{{kJ}}{{kg}} + \left( {\frac{{15m/s^2 }}{2} \times \frac{{1km}}{{1000m}}} \right) - 84.03\frac{{kJ}}{{kg}} \\
\omega = 1.9025\frac{{kJ}}{{kg}} \\
\end{array}
[/tex]
But the anwser should be 1.99 kJ/kg
Can anyone tell me what I did wrong? Are my specific enthalpys right?
Thanks
From my tables I get
hi=85.82 kJ/kg
he=84.03 kJ/kg
Energy equation reduces to:
[tex]
\begin{array}{l}
h_i + \frac{{V_i^2 }}{2} = \omega + h_e \\
\omega = h_i + \frac{{V_i^2 }}{2} - h_e \\
\omega = 85.82\frac{{kJ}}{{kg}} + \left( {\frac{{15m/s^2 }}{2} \times \frac{{1km}}{{1000m}}} \right) - 84.03\frac{{kJ}}{{kg}} \\
\omega = 1.9025\frac{{kJ}}{{kg}} \\
\end{array}
[/tex]
But the anwser should be 1.99 kJ/kg
Can anyone tell me what I did wrong? Are my specific enthalpys right?
Thanks