Hi there, I was hoping someone could check my solutions here to make sure I'm on the right track with these. We've been asked to find ALL values of z satisfying the following eqts - z= ln(-e^2) which I did by letting ln (-e^2)= ln|-e^2| + iarg(-e^2) = e^2 + i(pi + 2m(pi)) where m = 0, +1, -1, +2, -2...... are these all the solutions or am I supposed to go further with this to show ALL the solutions? I've another problem with ln(z)=1 because I have this = ln|z) +iarg(z) so 1=ln|z) when you compare real and imaginary parts. So then we get e^1=|z| so is z just 1/e? It just doesn't seem right to me, since we only get one solution and the question kinda hints at more than one (or maybe it' just the drink talking here!). Any help would be much appreciated. Thanks!