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Log subtraction help

  1. Sep 8, 2011 #1
    1. The problem statement, all variables and given/known data

    log6(x+6) - log6(x-4) = 3



    2. The attempt at a solution

    150/36 is what i get which i simplified to 25/6.
    but the program tells me im wrong can anyone think of how im getting this wrong
     
  2. jcsd
  3. Sep 8, 2011 #2
    anybody?
     
  4. Sep 8, 2011 #3

    lewando

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    Gold Member

    I get something close, what steps did you do to get at that answer?
     
  5. Sep 8, 2011 #4

    symbolipoint

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    Education Advisor
    Gold Member

    The logarithms (of the same base) are exponents so you can do:

    log6(x+6) - log6(x-4) = 3

    [tex] log_6 \frac{x+6}{x-4}=3[/tex]

    [tex] 6^3 = \frac{x+6}{x-4}[/tex]

    If you made that far, then you should find the rest of the steps.
     
  6. Sep 8, 2011 #5
    i figured it out now. i was squaring the base instead of cubing it. thanks for your help tho !!
     
  7. Sep 8, 2011 #6

    lewando

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    Gold Member

    So what did you get?
     
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