Logarithm Function: Properties and Solutions [Attached Image]

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Homework Help Overview

The discussion revolves around the properties of logarithmic functions, specifically focusing on simplifying expressions involving logarithms. The original poster has attached an image of a problem related to logarithmic identities and their applications.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are exploring the simplification of the expression ##\log _3 \left( a^{\log _3 7} \right)## and questioning how to further simplify it. There are hints being exchanged regarding the relationships between different logarithmic forms and powers.

Discussion Status

Some participants have provided hints and suggestions for approaching the problem, while others are attempting to derive values for variables a, b, and c based on the logarithmic expressions. There is recognition of the need to address the positivity of these variables, and a hint has been introduced that may guide further exploration.

Contextual Notes

The problem specifies that variables a, b, and c must be positive, which raises concerns about the derived value for c being negative. Additionally, it is noted that these variables are irrational, but solving for them is not necessary to progress in the problem.

Victim
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Homework Statement

I have attached image of question.[/B]

Homework Equations

all the properties of log
a^(logₘn)=n^(logₘa)[/B]

The Attempt at a Solution

in the attached image
1534508914003-822972847.jpg
[/B]
 

Attachments

  • 1534508914003-822972847.jpg
    1534508914003-822972847.jpg
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##\log _3 \left( a^{\log _3 7} \right)## is of the form ##\log _3 \left( a^y \right)##, Can you simplify this further?
 
George Jones said:
##\log _3 \left( a^{\log _3 7} \right)## is of the form ##\log _3 \left( a^y \right)##, Can you simplify this further?
and then
 
Victim said:
and then
You tell us, George gave you a hint.
 
jedishrfu said:
You tell us, George gave you a hint.
OK by this method I got a=20 b=38 c=√(11)-25
Then they are in power of log₃7,log₇11 and log₁₁25.How to solve these powers
 
Victim said:
OK by this method I got a=20 b=38 c=√(11)-25
Then they are in power of log₃7,log₇11 and log₁₁25.How to solve these powers
The problem states that a, b, and c are positive. The value you give for c, ##\ \sqrt{11\,}-25\,,\ ## is negative.

Moreover, as it turns out, a, b, and c are all irrational. Fortunately, you do not need to solve for any of them to solve this problem.

Here is a hint that's different than the one given by George Jones.
Notice that ##\displaystyle \ X^{Y^ 2}=X^{Y\cdot Y}=\left(X^Y\right)^Y \ ##​
.
 

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