Logarithmic Help: Solving for z, m & n

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The discussion focuses on solving for variables z, m, and n using logarithmic properties in a homework problem. The initial attempts successfully calculated some values using the logarithm of 2 and 1.1, but similar methods failed for the remaining variables. Participants suggest approximating numbers like 2 and 3 as powers of 1.1, specifically 1.1^N and 1.1^M. The exercise emphasizes understanding the relationship between exponential and logarithmic forms to derive the correct values. Overall, the key is to apply logarithmic properties consistently to find the desired solutions.
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Homework Statement



http://img20.imageshack.us/img20/1476/mathproblemi.jpg


Homework Equations



Properties of logs.

The Attempt at a Solution



For the first two I did:

Int( \frac{Log(2)}{Log(1.1)} )

Doing this resulted in the correct answers for the first two boxes. When I try similar techniques to solve for z, m,n I get incorrect answers.

Anyone have tips or suggestions on how to go about finding these?
 
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Your task is to approximate 2 and 3 as 1.1^N and 1.1^M, and solve z from there.
 
If 1.1^7 is approximately 2 then 2^x is approximately (1.1^7)^x= 1.1^{7x}. That's the point of this exercise.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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