1. The problem statement, all variables and given/known data Log(2x-3)=log(4x-3)-logx 2. Relevant equations Logcl =logcr L=r 3. The attempt at a solution Quotient law of logs So I simplfied: Log(2x-3)=log(4x-3)/x Since same base: 2x-3=4x-3/x 2x^2-7x+3=0 (X-1)(x-6) The ans is supposed to be 3. I don't know what I'm doing wrong?