Long-term behaviour of solution to ODE: oscillatory

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Homework Help Overview

The discussion revolves around the long-term behavior of the solution to a differential equation, specifically focusing on its oscillatory nature. The original poster presents a solution and seeks clarification on the constant level around which the solution oscillates and the amplitude of that oscillation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the oscillation's minimum value and question whether it aligns with the constant level of Q=25. There is an attempt to understand how to derive the amplitude of oscillation from the remaining terms after considering the decay of the exponential component.

Discussion Status

Participants are actively engaging with the problem, with some offering insights into the relationship between the oscillatory components and trigonometric identities. There is recognition of the oscillation's behavior around the level of Q=25, and some guidance has been provided regarding the calculation of amplitude.

Contextual Notes

There is a mention of potential confusion regarding the original question's phrasing, particularly in relation to the minimum value and amplitude of oscillation. Participants are encouraged to revisit foundational concepts in trigonometry to aid their understanding.

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Homework Statement




I wondered if anyone could advise me how to proceed with this question.

The solution to the differential equation [tex]\frac{dQ}{dt}= \frac{1}{2}+\frac{1}{4}sin(t)-\frac{Q}{50}[/tex] is [tex]Q=25+(\frac{sin(t)-625cos(t)+63150e^{-\frac{t}{50}}}{2501})[/tex]

when [tex]Q_0= 50[/tex]

"The long-term behaviour of the solution is an oscillation about a certain constant level. What is this level? What is the amplitude of oscillation?"

I have plotted the solution and can see that it tails off and oscillates around what looks like a level of Q=25.

Would I be right in saying the oscillation's minimum will be Q=25, as this is the least value the expression for Q can realize?


My biggest problem is finding the amplitude of oscillation. I can see that the term involving 'e' at the end of the expression for Q goes to zero for large 't'. But I am not sure how to obtain the amplitude from what is left.
 
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The amplitude of ##A\cos(\omega t) + B\sin(\omega t)## is ##\sqrt{A^2+B^2}##.
 
jellicorse said:

Homework Statement




I wondered if anyone could advise me how to proceed with this question.

The solution to the differential equation [tex]\frac{dQ}{dt}= \frac{1}{2}+\frac{1}{4}sin(t)-\frac{Q}{50}[/tex] is [tex]Q=25+(\frac{sin(t)-625cos(t)+63150e^{-\frac{t}{50}}}{2501})[/tex]

when [tex]Q_0= 50[/tex]

"The long-term behaviour of the solution is an oscillation about a certain constant level. What is this level? What is the amplitude of oscillation?"

I have plotted the solution and can see that it tails off and oscillates around what looks like a level of Q=25.

Would I be right in saying the oscillation's minimum will be Q=25, as this is the least value the expression for Q can realize?

No, 25 is the value about which the solution oscillates in the long term.

My biggest problem is finding the amplitude of oscillation. I can see that the term involving 'e' at the end of the expression for Q goes to zero for large 't'. But I am not sure how to obtain the amplitude from what is left.

Compare the oscillatory part of your solution with the right hand side of the angle sum formula
[tex] R\cos(\phi + t) = R\cos\phi\cos t - R\sin\phi \sin t[/tex]
and hence determine [itex]R > 0[/itex] (and [itex]\phi[/itex], which you don't actually need here).
 
Thanks LCKurtz and pasmith... I need to revisit those angle sum formulas for a bit.
 
jellicorse said:
1. I have plotted the solution and can see that it tails off and oscillates around what looks like a level of Q=25.

2. Would I be right in saying the oscillation's minimum will be Q=25, as this is the least value the expression for Q can realize?


3. My biggest problem is finding the amplitude of oscillation. I can see that the term involving 'e' at the end of the expression for Q goes to zero for large 't'. But I am not sure how to obtain the amplitude from what is left.

1 you should be to see that at a glance at the formulae without plotting.

2. It oscillates about 25 as was already pointed out - have you copied the question correctly as it would be surprising if this were not asked? Especially as asking the minimum and asking the amplitude is practically the same question.

3. You should immediately realize that tha amplitude is going to be very little different from 625/2501 ≈ 1/4. In fact it seems to me that 626/2501 should be a very good approximation, the angle where the maximum occurs being approximately 1/626 radians.
 
Yes, the question did ask around what value it oscillates... After a bit of revision on the basic trig, I think I can see how this works now. Thanks.
 

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