How Do You Calculate Current in a Circuit with Multiple Resistors and Batteries?

  • Thread starter Thread starter mattmatt321
  • Start date Start date
  • Tags Tags
    Circuit Loop
AI Thread Summary
To calculate the current in a circuit with multiple resistors and batteries, it's essential to set up a loop equation correctly. A single loop may not suffice due to multiple unknown currents, so simplifying the circuit by combining parallel and series resistances is recommended. Identifying points of equal potential can help reduce complexity, allowing for a clearer analysis. Voltage sources in parallel can be replaced with a single equivalent source, maintaining the same voltage. Ultimately, focusing on a simplified loop that includes only necessary components will lead to a solvable equation for the current.
mattmatt321
Messages
7
Reaction score
0

Homework Statement



What is the magnitude i in the figure below, if all resistances are 4 ohms, and all batteries are ideal with an emf of 12.4 V?

http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c27/pict_27_70.gif

Homework Equations



The Attempt at a Solution



I realize I need to set up a loop equation. I decided to start in the lower left hand corner, turn left at the first "branch", go through the parallel resistors, through the unknown current, then turn left again, through the resistor, then left again, through the battery, and back to my starting point. I realize this completely disregards the rest of the circuit, but I do need a simple loop equation because as soon as I incorporate additional currents, I have too many unknowns and it can't be solved. My answer of 0.886 A through the given resistor is incorrect, and I have checked my loop equation multiple times.

The picture looks daunting, but I feel like it's very do-able; I just need a loop that will work. Can anyone point me in the right direction?
 
Physics news on Phys.org
A single loop equation is no use. You don't know if the same current is going through all the resistances in the loop. You need to replace all parallel and series resistances you can find. Some of the points of the circuit can be shown to have the same potential. For example the top left and bottom left corners. You can connect those with a wire.

If you ever get 2 of the voltage sources in parallel, you can replace them with a single voltage source of the same voltage if plus is connected to plus and minus to minus.
If they short each other something must have gone wrong.
 
It turns out that there is indeed a single loop that you can use. If your loop only follows wires and voltage sources, except for the chain of 4 resistors on the bottom left, than you can work out the voltage across those resistors, because the voltage sources always have 12.4 V across them, no matter what.

make a copy of the image, and erase all of the resistors, except for the 4 in the bottom left corner. you'll have one loop left.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top