How Does Velocity Addition in Special Relativity Ensure u' Remains Less Than c?

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Velocity addition in special relativity ensures that the resultant velocity u' remains less than the speed of light (c) by using specific equations that relate the velocities in different reference frames. When two frames S and S' move relative to each other at speed v, and an object moves with velocity u in frame S, the velocity u' in frame S' can be calculated using the velocity addition formulas. The discussion emphasizes that differentiation is unnecessary; instead, one should apply the Lorentz transformation equations to find the ratios of position and time. By substituting the appropriate values into the equations, it can be demonstrated that u' remains less than c. This reinforces the fundamental principle of relativity that no object can exceed the speed of light.
byerly100
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Consider two reference frames, S and S', moving with speed v (<c) with respect to one another along the x direction.

If a certain object moves with velocity u (u<c) with respect to S, and velocity u' with respect to S', use the velocity addition equations (in three dimensions) to show that u'<c.
 
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What have you tried?
 
byerly100 said:
Consider two reference frames, S and S', moving with speed v (<c) with respect to one another along the x direction.

If a certain object moves with velocity u (u<c) with respect to S, and velocity u' with respect to S', use the velocity addition equations (in three dimensions) to show that u'<c.
Just write down the equations and substitute.
Then find u"^2.
 
Are you saying to take the derivative of u'?
 
Don't you know the vdlocity addition eqs in SR?
If not you have to find the ratio dx'/dt' and dy'/dt' in terms of the unprimed using the Lorentz transformation eqs. Just take the ratios. Differentiation is not needed. If the know the eqs., just substitute.
 
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