- #1

Hoss

- 5

- 0

^{2}*R

Well isn't the power loss also = V

^{2}/ R

Now before you give me the regular answer of "this V is not the same as this V", i understand. However, from what i know from the voltage divider rule is that the V across the lines is a fraction of the V across the source (the rest is across the consumer's end resistance). Therefore if V (from the source) say doubles, the V across the lines should also double. And this will lead to the same power loss in the lines as before.

This is from what i know and I'm sure there's something wrong. Either I'm applying formulas incorrectly (eg. does the voltage divider rule even apply here?) or there's something i just don't know.

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I also have another question regarding the same thing:

Here are the variables i used (just to make it clear):

Ps - the power supplied by the generator

V1 - the voltage in the primary coil of the transformer

V2 - the voltage in the secondary coil of the transformer

I1 - the current in the primary coil

I2 - the current in the secondary coil

RL - the resistance of the transmission lines

Rc - the resistance of the consumer stuff

VL - the voltage drop across the transmission lines

Vc - the voltage drop across the consumer stuff

This is what i did,

Ps = V1*I1 = V2*I2

V2 = VL + Vc

Ps / I2 = I2*RL + I2*Rc

Ps = (I2^2)*RL + (I2^2)*Rc

Does this mean that if i decrease the current (as well as increase the voltage) by increasing the number of coils on the 2ndary coil, the power supplied by the generator decreases?? I'm really confused. Note that I'm in my 3rd semester in uni so there's still some stuff i didn't take (like voltage regulation...i just found out a few minutes ago that the output voltage of a transformer changes when the load changes...still don't understand it but that's not really my question here).