Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnetic Circuits

  1. Jul 1, 2007 #1

    TFH

    User Avatar

    Background: In the text books I’ve read the simple magnetic circuit is developed by first looking at a ferrous torus symmetrically wrapped with a condutor. Symmetry arguments indicate that the H field is radial through the torus and 0 on the inside and outside of the torus. Then from Ampere's law H is obtained.

    H = NI/L, N = number of turns, I = current, L = length around the torus (Pi R).

    I'm okay with this but next the shape of the torus changes to a square and the turns are bunched together on 1 leg of the square, say l1. And two assumptions are discussed: (1) flux is constand around the square core and (2) no leakage field. With these assumptions Ampere's law is used again to obtains the same equation for H except the Lenght "L" changes to match the square core.

    With a square core: L = l1 + l2 + l3 + l4. (l's are lengths of the square edges)

    My Problem: If I use Ampere's law for other paths I get "VERY" different answers.

    I can say integrate through l1 (that contains all the conductors) and would obtain: H = NI/l1. Or I could integrate say the half of the square that does not have a conductor and obtain:
    H = NI/(l2 +l3+l4), but here I is zero. So H=0 under the assumptions.

    So does the assumptions of no leakage field and constant flux for this geometry immediately cause a violation of Ampere's law?

    Thanks for any comments.
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you help with the solution or looking for help too?
Draft saved Draft deleted