Magnetic Field around a dipole calculation

crystalbrite
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Homework Statement


I've attached a page from the book Elements of Electromagnetics.

I was wondering how he gets from eq.8.20 to eq.8.21a.

What I would have done is sub in dl=a.d∅.a∅ and integrate ∅ between 0 and 2pi.

This would then give you A=[(2.μ0.I.pi.a)/(4.pi.r)].a

This is obviously wrong because it's not what he got. He does make an assumption that r>>a so maybe i have to do something with that.

Any help would be much appreciated

Thanks
 
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I think i forgot the attachment
 

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  • electromagnetics page.jpg
    electromagnetics page.jpg
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Its ok, i found the explanation in a book on google books. Its a bit long and tedious.

I guess no one here would be able to understand it which is why i got no reply. Oh well...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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