Magnetic field due to two wires

Click For Summary

Homework Help Overview

The discussion revolves around determining the magnetic field at a point P on the x-axis due to two parallel wires carrying currents in opposite directions. The original poster presents an equation for the magnetic field based on the geometry of the setup and attempts to analyze the contributions from each wire.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the symmetry of the problem and the cancellation of the y-components of the magnetic field. There is an exploration of the trigonometric relationships involved in determining the x-component of the magnetic field, with some questioning the dependence of the magnetic field on the distance d.

Discussion Status

The discussion is active, with participants providing feedback on each other's reasoning. There is acknowledgment of a mistake regarding the dependence of the magnetic field on both x and d, indicating a productive exchange of ideas and clarification of concepts.

Contextual Notes

The original poster notes that the assignment only provides the current I and the x-axis distance to point P, leading to questions about the relevance of the distance d in the final expression for the magnetic field.

Siune
Messages
24
Reaction score
0

Homework Statement


We have wires like in the picture and we want to know the value of magnetic field as
function of x:

NOTE: We want to know the magnetic field at point P ( P is on +x axis ) ( Which is totally arbitary!) The picture is there for just to give the idea.

189576A.jpg


R is the distance from each wire to point P.

Homework Equations



H = \frac{I}{2 \pi R }

The Attempt at a Solution



Okey, so the currents are going in opposite ways. By the right hand rule we get the direction of the magnetic field due to each wire!

We notice that the y-component cancels out ( due to symmetry ), and that the magnetic field is only the x component due to each wire at point P.

So by superposition principle we get the magnetic field at point P on x -axis:

H = sin(\theta) \frac{ I }{ \pi R }

Now sin(\theta) is the angle between x-axis and the distance R from each wire.

So we get from trigonometry:

H = \frac{d \cdot I }{ \pi R^2}

H = \frac{d \cdot I }{ (x ^2 + d ^2 ) \pi }

Not sure if this is right? At least the units match ( A / m ), but... problem is:

My assigment gives us only the current I and the x -axis distance to point P? So I assume the right answer of the magnetic field at point P should be independent of d? But that doesn't make sense to me.

Sincerely yours,
Siune
 
Physics news on Phys.org
Siune said:
We notice that the y-component cancels out ( due to symmetry ), and that the magnetic field is only the x component due to each wire at point P.

So by superposition principle we get the magnetic field at point P on x -axis:

H = sin(\theta) \frac{ I }{ \pi R }

Now sin(\theta) is the angle between x-axis and the distance R from each wire.

If θ is the angle between the x-axis and R, make sure you are using the correct trig function for getting the x-component.
 
Hmm, as the distance vector R from one wire and magnetic field from same wire are perpendicular I get that the x component of magnetic field by that wire

so sin(\theta) = \frac{d}{R}

and

R^2 = x^2 + d^2
?
 
Sorry, my mistake. You are entirely correct. The answer does depend on both x and d.
 
No problem at all, wouldn't have been the first time I make the mistake on the easiest part of the problem. ^^
 

Similar threads

Replies
2
Views
1K
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
11
Views
5K
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
16
Views
2K