Magnetic field due to two wires

AI Thread Summary
The discussion focuses on calculating the magnetic field at point P on the x-axis due to two parallel wires carrying currents in opposite directions. The magnetic field's y-component cancels out due to symmetry, leaving only the x-component. The correct formula for the magnetic field is derived using the superposition principle, with the x-component expressed in terms of the distance R and the angle θ. It is clarified that the magnetic field does indeed depend on both the x-axis distance and the distance d from the wires. The participants acknowledge and correct a misunderstanding regarding the dependence of the magnetic field on these variables.
Siune
Messages
24
Reaction score
0

Homework Statement


We have wires like in the picture and we want to know the value of magnetic field as
function of x:

NOTE: We want to know the magnetic field at point P ( P is on +x axis ) ( Which is totally arbitary!) The picture is there for just to give the idea.

189576A.jpg


R is the distance from each wire to point P.

Homework Equations



H = \frac{I}{2 \pi R }

The Attempt at a Solution



Okey, so the currents are going in opposite ways. By the right hand rule we get the direction of the magnetic field due to each wire!

We notice that the y-component cancels out ( due to symmetry ), and that the magnetic field is only the x component due to each wire at point P.

So by superposition principle we get the magnetic field at point P on x -axis:

H = sin(\theta) \frac{ I }{ \pi R }

Now sin(\theta) is the angle between x-axis and the distance R from each wire.

So we get from trigonometry:

H = \frac{d \cdot I }{ \pi R^2}

H = \frac{d \cdot I }{ (x ^2 + d ^2 ) \pi }

Not sure if this is right? At least the units match ( A / m ), but... problem is:

My assigment gives us only the current I and the x -axis distance to point P? So I assume the right answer of the magnetic field at point P should be independent of d? But that doesn't make sense to me.

Sincerely yours,
Siune
 
Physics news on Phys.org
Siune said:
We notice that the y-component cancels out ( due to symmetry ), and that the magnetic field is only the x component due to each wire at point P.

So by superposition principle we get the magnetic field at point P on x -axis:

H = sin(\theta) \frac{ I }{ \pi R }

Now sin(\theta) is the angle between x-axis and the distance R from each wire.

If θ is the angle between the x-axis and R, make sure you are using the correct trig function for getting the x-component.
 
Hmm, as the distance vector R from one wire and magnetic field from same wire are perpendicular I get that the x component of magnetic field by that wire

so sin(\theta) = \frac{d}{R}

and

R^2 = x^2 + d^2
?
 
Sorry, my mistake. You are entirely correct. The answer does depend on both x and d.
 
No problem at all, wouldn't have been the first time I make the mistake on the easiest part of the problem. ^^
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top