Magnetic Field from 2 cylinders

In summary, two infinitely long identical conductors carrying equal current densities in opposite directions and overlapping with a hollow region produce a constant magnetic field in all points within the hollow region. Along the y-axis at x=0, the magnetic field is equal to 4*pi*J*a. The magnetic field is also the same throughout the region. When calculating the magnetic force between the two conductors, the pressure is found to be equal to I1*I2/(pi*r^2*c^2) and will push the cylinders away due to the antiparallel current densities.
  • #1
bitty
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Homework Statement


Two infinitely long identical conductors carry equal current densities J in opposite directions parallel to the z-axis. They each have radius b and overlap so their centers are distance 2a apart. In the overlap a distance a from the center we have 0 current density (a hollow region).

What is the direction and magnitude of the magnetic field at the center of the hollow region?
Along the y-axis at x=0? All throughout the region?

Homework Equations


ampere's law

The Attempt at a Solution


I concluded the magnetic field everywhere inside the hollow region is the same:
B*2*pi*r=4*pi/c*J*pi*r^2 in cgs units for each cylinder
so B = 2*pi/c*J*(r2-r1)
where r2-r1 is a constant, r2 the distance from one cylinder to any pt inside the region and r1 equivalently for the other cylinder. since r2-r1 is vector addition it equals 2a, the distance between the centers of the cylinders, so B is constant for all 3. By the right hand rule, B points straight up in +y direction.

Could someone please check?
 
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  • #2
bitty said:
B*2*pi*r=4*pi/c*J*pi*r^2 in cgs units for each cylinder
so B = 2*pi/c*J*(r2-r1)
where r2-r1 is a constant, r2 the distance from one cylinder to any pt inside the region and r1 equivalently for the other cylinder. since r2-r1 is vector addition

No, r1 and r2 are both scalars, and that equation gives you only the magnitude of B. The direction of B is perpendicular to r (as given by the right hand rule).
 
  • #4
Re-solving for the magnetic field along the y-axis (at x=0)
since the two cylinders carry current in opposite direction we add the contributions from each cylinder. Each cylinder contributes a cosine component equal to a/r, where r is again the distance from one cylinder's axis to the point o interest, and 'a' is the distance from the axis of the cylinder to the y-axis.

Then B=2*pi*J*r *cos theta for each cylinder
==> B = 2*pi *J*r*a/r
so the superimposition is B= 4*pi*J*a along the axis, same answer as before.

Corrections/feedback please?
 
  • #5
bitty said:
This thread says they're vectors though...
https://www.physicsforums.com/showthread.php?t=161491

Yes, because those equations use the cross product instead of a simple multiplication. So if you want to write everything in terms of vectors:

B = 2*pi/c*J x (r2-r1)

For this specific problem, I find it easier to think in terms of scalars, but that's just personal preferences.
 
  • #6
these two problems though are analogous: in both we have 2 cylinders superimposed to create a hollow region. in this case though, the cylinders are identical and overlap instead of one being concentric to the other.

In this case, is my solution along the y-axis correct?

I have no idea who to solve for anywhere in the hollow region though, for the last part of the question, without claiming that the B field is the same everywhere in the hollow region. Can you toss me a bone?
 
  • #7
bitty said:
Re-solving for the magnetic field along the y-axis (at x=0)
since the two cylinders carry current in opposite direction we add the contributions from each cylinder. Each cylinder contributes a cosine component equal to a/r, where r is again the distance from one cylinder's axis to the point o interest, and 'a' is the distance from the axis of the cylinder to the y-axis.

Then B=2*pi*J*r *cos theta for each cylinder
==> B = 2*pi *J*r*a/r
so the superimposition is B= 4*pi*J*a along the axis, same answer as before.

Corrections/feedback please?

Yes, that's correct.
 
  • #8
bitty said:
these two problems though are analogous: in both we have 2 cylinders superimposed to create a hollow region. in this case though, the cylinders are identical and overlap instead of one being concentric to the other.

You're right, and you can apply the same equations from that thread to this problem. I just got a bit confused because in the initial post, you used * to represent a cross product.

I have no idea who to solve for anywhere in the hollow region though, for the last part of the question, without claiming that the B field is the same everywhere in the hollow region. Can you toss me a bone?

It is the same everywhere in the region, as per the other thread.
 
  • #9
Thanks! But using the same logic, the field would not be the same everywhere outside the cylinders because we would have it be proportional to 1/r not r. Understood.

One more question: when trying to find the magnetic force between the two conductors of infinite length 'l' with currents I1, I2 and
F= 2*I1*I2 *l/(c^2*r) and so the pressure would be
F/A = 2 *I1*I2/(2*pi*l*c^2*r^2)

so P= I1*I2/(pi*r^2*c^2), and it would be pushing the cylinders away because the carry antiparallel current densities.

Is that simple derivation correct, still using superimposition? Or is there anything specially I have naively overlooked in a case where the cylinders overlap?
 

FAQ: Magnetic Field from 2 cylinders

What is a magnetic field?

A magnetic field is a region in space where an electrically charged object experiences a force due to its motion. It is created by the movement of electrically charged particles, such as electrons, and is represented by magnetic field lines.

How does a magnetic field form between 2 cylinders?

A magnetic field forms between 2 cylinders when they have opposite magnetic polarities and are placed close together. The magnetic field lines from one cylinder will interact with the field lines from the other cylinder, resulting in a combined magnetic field between them.

What factors affect the strength of the magnetic field between 2 cylinders?

The strength of the magnetic field between 2 cylinders is affected by the distance between the cylinders, the strength of the magnetic materials used in the cylinders, and the alignment of the cylinders' magnetic polarities.

What are some real-world applications of magnetic fields from 2 cylinders?

Magnetic fields from 2 cylinders are commonly used in electric motors, generators, and transformers. They are also used in medical imaging machines, such as MRI scanners, to produce detailed images of the human body.

How can the magnetic field between 2 cylinders be measured?

The magnetic field between 2 cylinders can be measured using a device called a gaussmeter. The gaussmeter measures the strength and direction of the magnetic field at a specific point between the cylinders.

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