Magnetic Field from Protons vs Electrons

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 4K views
General Scientist
Messages
39
Reaction score
3
If an electron is moving in a circle in a magnetic field, it produces a magnetic field in accordance to the right hand rule. If a proton is moving in a circle in a magnetic field, would it produce a magnetic field in accordance to the left hand equivalent to the right hand rule.
 
Physics news on Phys.org
General Scientist said:
If an electron is moving in a circle in a magnetic field, it produces a magnetic field in accordance to the right hand rule. If a proton is moving in a circle in a magnetic field, would it produce a magnetic field in accordance to the left hand equivalent to the right hand rule.
You are correct as magnetic fields are created by moving charges, and the example would satisfy the criteria. Although, I assume it would be tiny compared to the surrounding magnetic field. The right hand rule would work for a proton.
 
The magnetic field for both is described by Biot-Savart's law. ## \vec{B}=\frac{\mu_o}{4 \pi} \frac{q \vec{v} \times\vec{r}}{|\vec{r}|^3} ##. With a negative charge on the electron, its magnetic field is opposite the direction given by ## \vec{v} \times \vec{r} ##.
 
  • Like
Likes   Reactions: berkeman
Charles Link said:
The magnetic field for both is described by Biot-Savart's law. With a negative charge on the electron, its magnetic field is opposite the direction given by ## \vec{v} \times \vec{r} ##.
So the positive charge of a proton would mean the magnetic field is just ##\vec{v} \times \vec{r}##?
 
General Scientist said:
So the positive charge of a proton would mean the magnetic field is just ##\vec{v} \times \vec{r}##?
See the part I added to post 3=the formula for ## \vec{B} ##.
 
Charles Link said:
See the part I added to post 3=the formula for ## \vec{B} ##.
Ok. Thank you.
 
  • Like
Likes   Reactions: berkeman and Charles Link