Magnetic Field inside a Solenoid (Please explain this answer to me)

AI Thread Summary
The discussion revolves around calculating the magnetic field inside a solenoid with specific dimensions and current. The formula used is the magnetic field of an ideal solenoid, which incorporates the permeability constant, current, and number of turns. The user initially struggles to understand how to arrive at the given answer of 4.2 x 10^-2 T, questioning the relevance of cross-sectional area. Ultimately, the user resolves their confusion after two hours of contemplation. This highlights the problem-solving process in physics homework related to magnetic fields.
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Homework Statement


Q5. A solenoid is 3.0 cm long and has a radius of 0.50 cm. It is wrapped with 500 turns of wire carrying a current of 2.0 A. T


Homework Equations



Magnetic field of an ideal solenoid = permeability constant (1.257E-6) * current * number of turns

The Attempt at a Solution



The given answer is: 4.2 x 10-2 T

I don't understand how to get this answer. From what my book says, the magnetic field is independent of cross-sectional area and only deals with semi-infinite solenoids. Please help!
 
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err nvm, I figured it out. I was seriously staring at this thing for two hours and then finally figure it out after I post it ><
 

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