Magnetic field of a moving charge

[squeak]

Homework Statement

A negative charge q = −3.20×10^-6C is located at the origin and has velocity υ⃗ =(7.50×10⁴m/s)ι^+((−4.90)×10⁴m/s)j^.
At this instant what is the magnetic field produced by this charge at the point x = 0.230 m , y = -0.300 m , z= 0? Give the x, y and x components

Homework Equations

B = u₀/4π. (qv x r)/r²

The Attempt at a Solution

So to find B_x I've tried using r = 0.230 and v = 7.5x10⁴ giving 10^-7 x 3.2 x 10^-6 x 7.5 x 10⁴/0.230². However i have a feeling I can't just take the x/y components individually. I know that a cross product goes to 1 if the components are perpendicular and 0 if they are parallel and feel like this will help but i just can't put it all together to give me the correct answer. any hints would be very much appreciated!

 

[Simon Bridge]

You are correct - you cannot just take the components individually like that. You have a vector equation, why not use it?
Do you know how to evaluate a cross product between two arbitrary vectors?