How Does the Radius Affect the Magnetic Field Inside a Solenoid?

AI Thread Summary
The discussion focuses on calculating the magnetic field inside an infinitely long solenoid using Ampère's law. It clarifies that the differential length, dl, is simply L when integrated along the solenoid's length, as the magnetic field is parallel to the solenoid's axis. The enclosed current, Ienc, is determined by multiplying the current I by the number of turns per unit length, N. The radius of the solenoid does not affect the magnetic field, which remains uniform inside the solenoid. The conclusion emphasizes that the magnetic field outside the solenoid is zero, reinforcing that only the internal field matters for this calculation.
Chip90
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Homework Statement



There is an infinetly long solenoid with current I, radius R, and N loops/unit length. Find the B field in the axis of the solenoid.

Homework Equations



792d084dfe4651c02d935c1490df17cd.png



The Attempt at a Solution



So that eq. can be narrowed to

B integral dl = Uo I

the only problem is I can't find dl its not 2*pi*R, 2r, 2RN... I am not sure what's wrong here.

I've made a similar diagram where the two edges and the side on the outside have a B field of 0.

solxsect.gif


Any ideas?
 
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any ideas? I also got
'
sol2.gif


but now sure how they got that from amperes law? ir is that the answer? thanks.
 

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That's correct. The differential length is simply L when integrated, since the magnetic field runs parallel to the axis of the solenoid. The enclosed current Ienc is the current I running through each turn multiplied by the number of turns in the solenoid, or N*I.

Hopefully that helps.
 
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?
 
Last edited:
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

You draw the gaussian loop enclosing only half of the inside of the solenoid and the other half s outside. There is no "r" because dl = L when integrated over the length of the solenoid.

Because B does not depend on the radius of the solenoid, the B field inside the solenoid is uniform, much like the E-field between a parallel plate capacitor is uniform.
 
ahha that makes sense.. thanks!
 
Chip90 said:
so in Amperes law.. dl= N*I ? How do I factor in the radius then? Or does it not matter?

nvm i see that your saying that Ienc= I*N correct?

but I am still left with R? How do I factor that in?

The vertical components don't matter since it's a dot product. The length outside of the solenoid is infinitely far away. At a point infinitely far away the magnetic field is 0, therefore it doesn't matter. That leaves the only important part as the horizontal line inside the solenoid. Therefore it's simply L (or X in this case.)
 
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