Magnetic field of helmoholtz apparatus

AI Thread Summary
The user is attempting to calculate the magnetic field of a Helmholtz apparatus using the formula B = 0.7155NI/R. With values of N=130, I=1.82, and R=0.15m, the calculated magnetic field is 1128.6, which is considered excessively high. There is a request for assistance in identifying potential errors in the calculation. Clarification is sought regarding the units used in the formula, with a reference to the SI units for the Helmholtz coil provided. Accurate unit conversion and verification of the formula's parameters are essential for correct results.
noname1
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I am trying to calculate the magnetic field of an experiment with the apparatus but my values are way too high and i can't figure out what i am doing wrong

I am using the formula B = 0.7155NI/R

N= 130
I=1.82
R=15cm=.15m

calculating this i get 1128.6 which is too much of a value for the magnetic field, any help would be appreciated
 
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What units are your equation in? Look here for the formula in SI units
http://en.wikipedia.org/wiki/Helmholtz_coil"
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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