Magnetic Field Strength in a Solenoid at t = 1 ms

AI Thread Summary
The discussion focuses on determining the magnetic field strength inside a solenoid at t = 1 ms. Initially, there is confusion regarding the difference between electromotive force (emf) and magnetic field strength. It is clarified that emf is not the same as the magnetic field. After some deliberation, the participant discovers the relevant equation for the magnetic field of a solenoid and calculates the magnetic field strength based on the inductor's current at the specified time. The thread concludes with a successful application of the formula to find the magnetic field strength.
vysero
Messages
134
Reaction score
0

Homework Statement



What is the magnitude of the magnetic field inside the solenoid at t = 1 ms?

Homework Equations



Not sure

The Attempt at a Solution



Well I would make an attempt but firstly I have a question. What I want to know is the above question simply referring to the emf of the solenoid? Is the emf the same thing as the magnetic field? I cannot seem to find an equation relating magnetic fields and inductors.
 
Physics news on Phys.org
No, it is asking about the strength of the magnetic field, which is not the same as the emf.
 
axmls said:
No, it is asking about the strength of the magnetic field, which is not the same as the emf.

Right moments after posting this I found an equation for the B of a solenoid. I then found i for the inductor based on the given time and was able to find the stregth of B from that.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top