- #1
six789
- 127
- 0
Two oppositely charged objects exert a force of attraction of 8.0N on each other. What will be the new force of attraction if the objects are moved to a diustance four times their original distance of separation?
i did this..
F=kq1*q2/4r
8.0N=9.0x10^9 (1)(1)/4r
r=1.125x10^9m
how can you find the new force...HELP.. i don't know wat to do next here...
the right answer in my book is 0.50N.
i did this..
F=kq1*q2/4r
8.0N=9.0x10^9 (1)(1)/4r
r=1.125x10^9m
how can you find the new force...HELP.. i don't know wat to do next here...
the right answer in my book is 0.50N.
Last edited: