Magnetic fields, lorentz force

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SUMMARY

The discussion focuses on calculating the uniform magnetic field required for an electron to travel in a straight line between two parallel plates under specific conditions. The electron is accelerated through a potential difference of V1=0.868 kV and enters a region with a potential difference of V2=91.2 V across a separation of d=21.9 mm. The key equations used include KE = QV, E = -V/d, and the relationship FE = FB, leading to the conclusion that the magnetic field vector must be directed along the x or y-axis to counteract the electric force along the z-axis, resulting in a magnetic field of 2.38e-4 T.

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  • Understanding of Lorentz force and its components
  • Familiarity with electric fields and potential differences
  • Knowledge of vector notation and cross products
  • Basic principles of electromagnetism, particularly regarding charged particles
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  • Learn about the relationship between electric and magnetic fields in particle motion
  • Explore the concept of potential difference and its effects on charged particles
  • Investigate the behavior of charged particles in uniform magnetic fields
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popo902
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Homework Statement



an electron accelerated from rest through potential difference V1=0.868 kV enters the gap between two parallel plates having separation d = 21.9 mm and potential difference V2= 91.2 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap?

Homework Equations



KE = QV
KE = 1/2 mv^2
E= -V/d
E=vB
FE = QE
FB = Qv X B

The Attempt at a Solution



i know that Q and m are the charge an mass of an electron
to calculate E, i used V2, 91.2V.
I use the equations to solve for v

i know that for the electron to go straight through, the FE=FB,
so i got E = vB
then i solved for B

and since B is a cross product of vectors on an xy plane, It HAS to only have a direction perpendicular to them on the z axis

it asks for the answer in vector notation so
in the end, i get 0i + 0j + 2.38e-4k T
but it's wrong...
I have a feeling that this is supposed to be one of the easier questions too :S
 
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popo902 said:
[...] and since B is a cross product of vectors on an xy plane, It HAS to only have a direction perpendicular to them on the z axis
Almost!, but not quite. :frown: The electric force is already along the z-axis (the problem statement mentioned something about a lower plate, implying there is an upper plate, implying that one plate is above the other). Which means to counteract the electric force, the magnetic force you are looking for must also be along the z-axis!

So the magnetic field vector must be perpendicular to the force vector and also the velocity vector. But since the force vector is on the z axis, the magnetic field vector must be along some other axis.
it asks for the answer in vector notation so
in the end, i get 0i + 0j + 2.38e-4k T
but it's wrong...
I have a feeling that this is supposed to be one of the easier questions too :S
The magnitude of your magnetic field vector looks good to me. :approve:. (Just work on the direction. :smile:)

[Edit: A figure or something defining the axes would be helpful here. The problem statement doesn't say along which axis the electron is moving, so there isn't enough information given in the problem statement as it is. But I'm guessing that the up/down axis is the z-axis in my above comments. The rest depends along which other axis (x or y) the electron is moving. In any case, once you know how the axes are defined, you can use the right hand rule (or the definition of the cross product) to find the solution.]
 
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