Magnetic Force on a Moving Charge

AI Thread Summary
The problem involves calculating the magnetic force on a charged dust particle moving through a magnetic field. The magnetic field strength is 0.5 T, directed east, while the dust particle has a charge of -8 x 10^-18 C and moves downward at 0.6 cm/s. The formula used for the magnetic force is F = qv X b, where the direction of the force is determined by the right-hand rule. There is confusion regarding the conversion of the particle's speed from cm/s to m/s and the correct application of the formula. The discussion emphasizes the need for clarity in the attempted solution and the importance of understanding vector direction in magnetic force calculations.
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Homework Statement


A magnet produces a 0.5 T field between its poles, directed to the east. A dust particle with charge q = -8 times 10-18 C is moving straight down at 0.6 cm/s in this field. What is the magnitude and direction of the magnetic force on the dust particle?


Homework Equations



F= qv X b

The Attempt at a Solution



Tried converting .6 cm/s into m/s and solving since the sin (90) would still be 1, but it keeps telling me I am wrong.
 
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Hi, you need to be more explicit as to what you have tried which you said did not correspond to the correct answer. What is your answer? It's a vector isn't it?
 
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