Magnetic force on a wire problem

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Homework Help Overview

The problem involves calculating the magnetic force per unit length on a wire within a bundle of insulated wires carrying current. The context includes the application of Ampere's law and the magnetic field generated by the enclosed current.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the number of wires contributing to the magnetic field and the application of relevant equations. There are questions regarding the correctness of the calculated force per unit length and the direction of the magnetic force.

Discussion Status

Some participants express uncertainty about the calculations, while others confirm the approach seems reasonable. There is a recognition that the original poster may need to clarify the direction of the magnetic force. Multiple interpretations of the problem's requirements are being explored.

Contextual Notes

The original poster mentions potential issues with logic or calculations, and there is a reference to the possibility of discrepancies in the textbook. The discussion highlights the need for both magnitude and direction in the response.

Sheneron
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Homework Statement


A packed bundle of 100 long, straight, insulated wires forms a cylinder of radius R = 0.500 cm.
(a) If each wire carries 2.00 A, what are the magnitude and direction of the magnetic force per unit length acting on a wire located 0.200 cm from the center of the bundle?

Homework Equations


F= ILB

B = \frac{\mu_{0}I_{enc}}{2\pi r}

The Attempt at a Solution



Here is what I did to get the solution:

I can find the number of wires in out to where the radius equals 0.002m.
\frac{\pi(0.002)^2}{\pi(0.005)^2}*100 = Number of Wires

That gives me 16 wires and since each has 2 amps the current enclosed = 32 A.

Using ampere's law:

B = \frac{(4\pi * 10^{-7})(32)}{2\pi(0.002)}

B = 0.0032

Knowning B I can find the force per unit length on one wire with 2 amps of current.

\frac{F}{L} = (2)(0.0032)

That equals 0.0064 N/m

That answer is wrong and I can't figure out why. If anyone can help it would be appreciated. Thanks
 
Last edited:
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Do you mean .0064N/m
 
yes I did, sorry
 
I can't figure out what could be wrong with this.
 
Looks okay to me too..
 
The instructions request the direction as well as the magnitude...
You have the magnitude: 6.34mN/m
I'd say you need to articulate the direction ("inward"), ,otherwise you are absolutely correct.
:-p
 
Well I got an answer of 6.4mN/m which is not the right answer. 3 options. Something is wrong in my logic. Something is wrong in my calculations. Or the books is wrong.
 

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