Magnetic Force on Electron near Long Wire

AI Thread Summary
A long wire carrying a 15-A current along the +y axis generates a magnetic field that affects an electron located at x=6 cm. The correct application of the right-hand rule indicates that the magnetic field at this point is directed along the negative z-axis. The electron, moving away from the wire along the +x axis at a speed of 10^6 m/s, experiences a force due to this magnetic field. Understanding the orientation of the magnetic field is crucial for calculating the force on the electron. The discussion emphasizes the importance of visualizing magnetic field directions in relation to current flow.
lha08
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Homework Statement


A long, straight wire carries a 15-A current along the +y axis. What is the force on an electron located instantaneously at x= 6 cm and moving with a speed of 10^6 m/s in the following directions:
a) away from the wire along the +x axis?

Homework Equations


The Attempt at a Solution


Like i know that the current is flowing up the y-axis but like i tried using the right hand rule to find the current (my thumb points towards current and fingers curl downwards--so magnetic field is downward..is that right??
 
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I'm not sure what you mean by the magnetic field is "downward"

I've uploaded a picture showing the correct direction of the magnetic field in the x-y plane.[PLAIN]http://img704.imageshack.us/img704/6974/98705090.jpg

so at a point along the positive x-axis, the magnetic field is directed along the negative z-axis.
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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