Magnetic forces aon currents and magnetic induction

AI Thread Summary
The discussion centers on calculating the magnetic force on a square coil in a uniform magnetic field. Given a magnetic field strength of 0.80 T, a square coil with a side length of 20 cm, and a current of 5.0 A, the magnetic force on the lower section of the loop is determined to be 5. The conversation emphasizes the importance of applying the right formulas and understanding the direction of the magnetic force. Participants are encouraged to engage more actively in problem-solving. The thread highlights the need for collaborative learning in physics concepts.
abc123
Messages
1
Reaction score
0
HELP ME PLEASE!

Given B=0.80 T, a square coil with a single loop with length of each side of 20 cm, a current of 5.0 A where there is an external constant uniform magnetic field, what are the size and the direction of the magnetic force on just the lower section of the loop due to the 0.80 T field?
 
Physics news on Phys.org
The answer is 5.




seriously, have you tried anything?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top