Magnetic Forces on Charged Particles

AI Thread Summary
A particle with a charge of +8.4 µC and a speed of 55 m/s enters a magnetic field of 0.30 T, prompting calculations for the magnetic force. The initial attempt incorrectly interpreted the magnetic field strength as 30 T instead of 0.30 T. Correcting this, the magnetic force was recalculated, resulting in a value of 6.93E-5 N. The direction of the force is determined by the vector nature of magnetic forces, which depend on the angle between the velocity and magnetic field. Accurate understanding of the magnetic field's magnitude is crucial for solving such problems.
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Homework Statement



A particle with a charge of +8.4 µC and a speed of 55 m/s enters a uniform magnetic field whose magnitude is 0.30 T. For each of the cases in the drawing, find the magnitude and direction of the magnetic force on the particle.

21_02.gif


Homework Equations



B = F / [q(VsinΘ)]

The Attempt at a Solution



Ok, for case (a) I tried the following:

- 30 = F / [8.4*10^6(55sin30)]
- 30 = F / 27.5
- 30 * 27.5 = F
- F= 825 N

Where am I going wrong? Thanks!
 
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Welcome to PF.

Remember these are vectors and the Force vector will be in what direction?

And it is determined by what scalar operation?
 
Also note your B field is .3T
 
Ah, of course. I'm not sure how I kept reading B as "30" rather than ".3" lol.

So the actual answer would be 6.93E-5.

Thanks!
 
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