Magnetic resonancy, Zeeman effect

AI Thread Summary
The discussion focuses on a magnetic resonance experiment involving hydrogen atoms in their ground state, where a constant magnetic field B_0 and an oscillating magnetic field B_ω are used to explore energy level transitions. The participant expresses confusion about quantum numbers, particularly how to account for energy level splitting when the quantum number l is zero. They clarify that the atoms must absorb photons to transition to a higher energy level (n=2) and discuss the magnetic moment of electrons due to their spin. The interaction energy between the magnetic dipole and the external field is calculated, leading to the conclusion that the resonance frequency can be determined using the formula ω = μ_B B_0/ħ, resulting in an approximate frequency of 1.75 x 10^11 Hz. The calculations and understanding of the concepts appear to be validated by the participants.
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Homework Statement


A magnetic resonancy experiment is realized using hydrogen atoms in their ground state. A constant magnetic field B_0 duplicate the magnetic energy levels in the atoms and an oscillating magnetic field B_ \omega is synchronized to the frequency that corresponds to the transition between these levels. Calculate the value of the frequency of resonance for a field B_0 =2000G.

Homework Equations


Somes.

The Attempt at a Solution


I think I know how to solve the problem if the atoms weren't in their ground state.
What makes me doubt about my whole understanding of the quantum numbers and the hydrogen atom is...
If n=1, the quantum number l must be worth 0.
Since m_l goes from -l to l, it must also be worth 0.
So how can there be any duplication of lines?

Edit: It isn't stated but I guess I must assume that the atoms absorb photons to reach the shell n=2. Is this right?
 
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The electrons have magnetic moment due to their spin, too.
There is no lines mentioned; you need to calculate the splitting of the level.

ehild
 
Ah I see. I totally confused 2 effects.
Is this formula right (I found it in hyperphysics with some substitutions) \mu _S=-\frac{2 \mu _B S}{\hbar}? If so, this is worth -\sqrt 3 \mu _B.
I don't really know how to calculate the difference of energy of the electrons due to the external magnetic field.
 
The interaction energy of dipole and field is equal to the product of the field multiplied by the parallel component of the momentum. The magnetic momentum of the electron can align only parallel and antiparallel to the field.

ehild
 
ehild said:
The interaction energy of dipole and field is equal to the product of the field multiplied by the parallel component of the momentum. The magnetic momentum of the electron can align only parallel and antiparallel to the field.

ehild
Thank you very much, I understand now.
So you mean \Delta E = \pm \mu _B B.
Also, E= \hbar \omega.
This gives me \omega = \frac{\mu _B B_0}{\hbar}. B_0 is worth 2 teslas.
I reach \omega \approx 1.75 \times 10 ^{11} Hz. Does this looks good?
 
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