Magnetism: Solving Question on Induced E in Windings of Coil

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To find the induced electromotive force (emf) in a tightly wound circular coil with 81.9 turns and a radius of 0.1 m, the magnetic flux approach is suggested. The magnetic field increases from 0 T to 0.851 T over 0.364 seconds, leading to the use of the equation emf = -dΦ/dt, where Φ represents the magnetic flux. Since the number of turns (N) and the area (A) remain constant, the formula simplifies to emf = -NA dB/dt, requiring the calculation of dB/dt. The discussion emphasizes the need to determine the rate of change of the magnetic field to solve for the induced emf.
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Homework Statement




Given: A tightly wound circular coil has
81.9 turns , each of radius 0.1 m. The uniform
magnetic field is in a direction perpendicular
to the plane of the coil. The field increases
linearly from 0 T to 0.851 T in a time of
0.364 s .
What E is induced in the windings of the
coil?
Answer in units of V.

Homework Equations



emf=Blv
emf(average)=magnetic flux/time


The Attempt at a Solution


I think this can be solved using magnetic flux, but i don't reallly know how to go about doing it
 
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tayi said:

Homework Equations



emf=Blv
emf(average)=magnetic flux/time


The Attempt at a Solution


I think this can be solved using magnetic flux, but i don't reallly know how to go about doing it

Start with your equation

emf = -dΦ/dt where Φ=NBA, thus your equation becomes

emf = -d/dt(NBA)

N and A are constant so emf=-NA dB/dt. So how you would get dB/dt which is the rate of change of the magnetic field per unit time.
 
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