Magnitude and direction a uniform magnetic field

AI Thread Summary
A user encountered difficulty solving a physics problem involving a proton moving in a uniform magnetic field. They initially used the formula B = F/qv sin(theta) but struggled with the values, particularly the mass of the proton. Guidance was provided on employing the right-hand rule and vector math to determine the magnetic field's magnitude and direction. Ultimately, the user resolved the issue by correctly incorporating the proton's mass and applying the right-hand rule effectively. The discussion highlights the importance of understanding fundamental concepts in magnetism and the utility of problem-solving techniques.
physics_ash82
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magnetism

Hi I'm stuck on this problem I its got to be something simple.Here goes...

A proton moves perpendicularly to a uniform magnetic field B at 1.0x10^7 m/s and exhibits an acceleration of 2.0x10^13m/s^2 in the + x-direction when its velocity is in the + z-direction. Determine the magnitude and direction of the field.

I have been trying to use B= F/qvsin(theta)
theta = 1
q = 1.6x10^-19


and then I have the problem :blushing: So any other help would be useful thankx

ash
 
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Think about the use of the right hand rule and think it through. If our not to secure with that and you aregood at vectors math, try working out the cross products and such. If your still stuck let us know what's up.

P.S; the magnitude is given.
 
The right hand rule is a great tool if used. Try to use it to work out the problem, it makes things so much simpler.
 
Thanx

I figured it out I was using the right formula and had forgotten that the mass of the proton is 1.67x10^-27 and I was using the charge which was 1.6 x10^-19.. but thank you for the idea on right hand rule that helped with the 2nd part.

ash:smile:
 
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